JEE Math Practice Question
Let $${a_1}$$, $${a_2}$$, $${a_3}$$, ......... ,$${a_{49}}$$ be in A.P. such that $$\sum\limits_{k = 0}^{12} {{a_{4k + 1}}} = 416$$ and $${a_9} + {a_{43}} = 66$$. $$a_1^2 + a_2^2 + ....... + a_{17}^2 = 140m$$, then m is equal to
- A.33
- B.66
- C.68
- D.34
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