JEE Math Practice Question
If A > 0, B > 0 and A + B = $${\pi \over 6}$$, then the minimum value of tanA + tanB is :
- A.$$\sqrt 3 - \sqrt 2 $$
- B.$$2 - \sqrt 3 $$
- C.$$4 - 2\sqrt 3 $$
- D.$${2 \over {\sqrt 3 }}$$
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