JEE Math Practice Question
If $${(10)^9} + 2{(11)^1}\,({10^8}) + 3{(11)^2}\,{(10)^7} + ......... + 10{(11)^9} = k{(10)^9},$$, then k is equal to :
- A.100
- B.110
- C.$${{121} \over {10}}$$
- D.$${{441} \over {100}}$$
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