JEE Math Practice Question
Let $A B C D$ be a tetrahedron such that the edges $A B, A C$ and $A D$ are mutually perpendicular. Let the areas of the triangles $\mathrm{ABC}, \mathrm{ACD}$ and ADB be 5,6 and 7 square units respectively. Then the area (in square units) of the $\triangle B C D$ is equal to :
- A.$\sqrt{110}$
- B.12
- C.$\sqrt{340}$
- D.$7 \sqrt{3}$
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