JEE Math Practice Question
Let the line passing through the points $(-1,2,1)$ and parallel to the line $\frac{x-1}{2}=\frac{y+1}{3}=\frac{z}{4}$ intersect the line $\frac{x+2}{3}=\frac{y-3}{2}=\frac{z-4}{1}$ at the point $P$. Then the distance of $P$ from the point $Q(4,-5,1)$ is
- A.$5 \sqrt{6}$
- B.$5$
- C.$5 \sqrt{5}$
- D.$10$
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