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JEE Math Practice Question

The distance of the line $\frac{x-2}{2}=\frac{y-6}{3}=\frac{z-3}{4}$ from the point $(1,4,0)$ along the line $\frac{x}{1}=\frac{y-2}{2}=\frac{z+3}{3}$ is :

  1. A.$\sqrt{17}$
  2. B.$\sqrt{13}$
  3. C.$\sqrt{15}$
  4. D.$\sqrt{14}$

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