JEE Math Practice Question
Let $\mathrm{L}_1: \frac{x-1}{2}=\frac{y-2}{3}=\frac{z-3}{4}$ and $\mathrm{L}_2: \frac{x-2}{3}=\frac{y-4}{4}=\frac{z-5}{5}$ be two lines. Then which of the following points lies on the line of the shortest distance between $\mathrm{L}_1$ and $\mathrm{L}_2$ ?
- A.$\left(\frac{14}{3},-3, \frac{22}{3}\right)$
- B.$\left(2,3, \frac{1}{3}\right)$
- C.$\left(\frac{8}{3},-1, \frac{1}{3}\right)$
- D.$\left(-\frac{5}{3},-7,1\right)$
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