JEE Math Practice Question

Let $$\mathrm{P}$$ be the point of intersection of the lines $$\frac{x-2}{1}=\frac{y-4}{5}=\frac{z-2}{1}$$ and $$\frac{x-3}{2}=\frac{y-2}{3}=\frac{z-3}{2}$$. Then, the shortest distance of $$\mathrm{P}$$ from the line $$4 x=2 y=z$$ is

1. A.$$\frac{3 \sqrt{14}}{7}$$
2. B.$$\frac{5 \sqrt{14}}{7}$$
3. C.$$\frac{\sqrt{14}}{7}$$
4. D.$$\frac{6 \sqrt{14}}{7}$$