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JEE Math Practice Question

Let the line $$\mathrm{L}$$ intersect the lines $$x-2=-y=z-1,2(x+1)=2(y-1)=z+1$$ and be parallel to the line $$\frac{x-2}{3}=\frac{y-1}{1}=\frac{z-2}{2}$$. Then which of the following points lies on $$\mathrm{L}$$ ?

  1. A.$$\left(-\frac{1}{3}, 1,-1\right)$$
  2. B.$$\left(-\frac{1}{3},-1,1\right)$$
  3. C.$$\left(-\frac{1}{3},-1,-1\right)$$
  4. D.$$\left(-\frac{1}{3}, 1,1\right)$$

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