JEE Math Practice Question
Let $$\mathrm{P}(3,2,3), \mathrm{Q}(4,6,2)$$ and $$\mathrm{R}(7,3,2)$$ be the vertices of $$\triangle \mathrm{PQR}$$. Then, the angle $$\angle \mathrm{QPR}$$ is
- A.$$\cos ^{-1}\left(\frac{7}{18}\right)$$
- B.$$\frac{\pi}{6}$$
- C.$$\cos ^{-1}\left(\frac{1}{18}\right)$$
- D.$$\frac{\pi}{3}$$
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