JEE Math Practice Question
Consider a $\triangle A B C$ where $A(1,3,2), B(-2,8,0)$ and $C(3,6,7)$. If the angle bisector of $\angle B A C$ meets the line $B C$ at $D$, then the length of the projection of the vector $\overrightarrow{A D}$ on the vector $\overrightarrow{A C}$ is :
- A.$\frac{37}{2 \sqrt{38}}$
- B.$\sqrt{19}$
- C.$\frac{39}{2 \sqrt{38}}$
- D.$\frac{\sqrt{38}}{2}$
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