JEE Math Practice Question
Let the system of linear equations $-x+2 y-9 z=7$ $-x+3 y+7 z=9$ $-2 x+y+5 z=8$ $-3 x+y+13 z=\lambda$ has a unique solution $x=\alpha, y=\beta, z=\gamma$. Then the distance of the point $(\alpha, \beta, \gamma)$ from the plane $2 x-2 y+z=\lambda$ is :
- A.11
- B.7
- C.13
- D.9
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