JEE Math Practice Question
The distance of the point ($$-1,9,-16$$) from the plane $$2x+3y-z=5$$ measured parallel to the line $${{x + 4} \over 3} = {{2 - y} \over 4} = {{z - 3} \over {12}}$$ is :
- A.13$$\sqrt2$$
- B.26
- C.20$$\sqrt2$$
- D.31
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