JEE Math Practice Question
The line $$l_1$$ passes through the point (2, 6, 2) and is perpendicular to the plane $$2x+y-2z=10$$. Then the shortest distance between the line $$l_1$$ and the line $$\frac{x+1}{2}=\frac{y+4}{-3}=\frac{z}{2}$$ is :
- A.9
- B.7
- C.$$\frac{19}{3}$$
- D.$$\frac{13}{3}$$
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