JEE Math Practice Question
If a plane passes through the points $(-1, k, 0),(2, k,-1),(1,1,2)$ and is parallel to the line $\frac{x-1}{1}=\frac{2 y+1}{2}=\frac{z+1}{-1}$, then the value of $\frac{k^2+1}{(k-1)(k-2)}$ is :
- A.$\frac{17}{5}$
- B.$\frac{6}{13}$
- C.$\frac{13}{6}$
- D.$\frac{5}{17}$
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