JEE Math Practice Question
Let the plane $\mathrm{P}: 8 x+\alpha_{1} y+\alpha_{2} z+12=0$ be parallel to the line $\mathrm{L}: \frac{x+2}{2}=\frac{y-3}{3}=\frac{z+4}{5}$. If the intercept of $\mathrm{P}$ on the $y$-axis is 1 , then the distance between $\mathrm{P}$ and $\mathrm{L}$ is :
- A.$\frac{6}{\sqrt{14}}$
- B.$\sqrt{14}$
- C.$\sqrt{\frac{2}{7}}$
- D.$\sqrt{\frac{7}{2}}$
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