JEE Math Practice Question
The shortest distance between the lines $$\frac{x+7}{-6}=\frac{y-6}{7}=z$$ and $$\frac{7-x}{2}=y-2=z-6$$ is :
- A.$$2 \sqrt{29}$$
- B.1
- C.$$\sqrt{\frac{37}{29}}$$
- D.$$\frac{\sqrt{29}}{2}$$
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