JEE Math Practice Question

If the two lines $${l_1}:{{x - 2} \over 3} = {{y + 1} \over {-2}},\,z = 2$$ and $${l_2}:{{x - 1} \over 1} = {{2y + 3} \over \alpha } = {{z + 5} \over 2}$$ are perpendicular, then an angle between the lines l2 and $${l_3}:{{1 - x} \over 3} = {{2y - 1} \over { - 4}} = {z \over 4}$$ is :

1. A.$${\cos ^{ - 1}}\left( {{{29} \over 4}} \right)$$
2. B.$${\sec ^{ - 1}}\left( {{{29} \over 4}} \right)$$
3. C.$${\cos ^{ - 1}}\left( {{2 \over {29}}} \right)$$
4. D.$${\cos ^{ - 1}}\left( {{2 \over {\sqrt {29} }}} \right)$$