JEE Math Practice Question
Let the plane ax + by + cz = d pass through (2, 3, $$-$$5) and is perpendicular to the planes 2x + y $$-$$ 5z = 10 and 3x + 5y $$-$$ 7z = 12. If a, b, c, d are integers d > 0 and gcd (|a|, |b|, |c|, d) = 1, then the value of a + 7b + c + 20d is equal to :
- A.18
- B.20
- C.24
- D.22
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