JEE Math Practice Question

Let $${{x - 2} \over 3} = {{y + 1} \over { - 2}} = {{z + 3} \over { - 1}}$$ lie on the plane $$px - qy + z = 5$$, for some p, q $$\in$$ R. The shortest distance of the plane from the origin is :

1. A.$$\sqrt {{3 \over {109}}} $$
2. B.$$\sqrt {{5 \over {142}}} $$
3. C.$${5 \over {\sqrt {71} }}$$
4. D.$${1 \over {\sqrt {142} }}$$