JEE Math Practice Question
Let L be a line obtained from the intersection of two planes x + 2y + z = 6 and y + 2z = 4. If point P($$\alpha$$, $$\beta$$, $$\gamma$$) is the foot of perpendicular from (3, 2, 1) on L, then the value of 21($$\alpha$$ + $$\beta$$ + $$\gamma$$) equals :
- A.102
- B.142
- C.136
- D.68
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