JEE Math Practice Question
The distance of the point (1, 1, 9) from the point of intersection of the line $${{x - 3} \over 1} = {{y - 4} \over 2} = {{z - 5} \over 2}$$ and the plane x + y + z = 17 is :
- A.$$19\sqrt 2 $$
- B.$$2\sqrt {19} $$
- C.38
- D.$$\sqrt {38} $$
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