JEE Math Practice Question
A perpendicular is drawn from a point on the line $${{x - 1} \over 2} = {{y + 1} \over { - 1}} = {z \over 1}$$ to the plane x + y + z = 3 such that the foot of the perpendicular Q also lies on the plane x – y + z = 3. Then the co-ordinates of Q are :
- A.(4, 0, – 1)
- B.(2, 0, 1)
- C.(1, 0, 2)
- D.(– 1, 0, 4)
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