JEE Math Practice Question
If an angle between the line, $${{x + 1} \over 2} = {{y - 2} \over 1} = {{z - 3} \over { - 2}}$$ and the plane, $$x - 2y - kz = 3$$ is $${\cos ^{ - 1}}\left( {{{2\sqrt 2 } \over 3}} \right),$$ then a value of k is :
- A.$$\sqrt {{3 \over 5}} $$
- B.$$ - {5 \over 2}$$
- C.$$ - {3 \over 2}$$
- D.$$\sqrt {{5 \over 3}} $$
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