JEE Math Practice Question
The coordinates of the foot of the perpendicular from the point (1, $$-$$2, 1) on the plane containing the lines, $${{x + 1} \over 6} = {{y - 1} \over 7} = {{z - 3} \over 8}$$ and $${{x - 1} \over 3} = {{y - 2} \over 5} = {{z - 3} \over 7},$$ is :
- A.(2, $$-$$4, 2)
- B.($$-$$ 1, 2, $$-$$1)
- C.(0, 0, 0)
- D.(1, 1, 1)
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