JEE Math Practice Question
The image of the line $${{x - 1} \over 3} = {{y - 3} \over 1} = {{z - 4} \over { - 5}}\,$$ in the plane $$2x-y+z+3=0$$ is the line :
- A.$${{x - 3} \over 3} = {{y + 5} \over 1} = {{z - 2} \over { - 5}}$$
- B.$${{x - 3} \over { - 3}} = {{y + 5} \over { - 1}} = {{z - 2} \over 5}\,$$
- C.$${{x + 3} \over 3} = {{y - 5} \over 1} = {{z - 2} \over { - 5}}\,$$
- D.$${{x + 3} \over { - 3}} = {{y - 5} \over { - 1}} = {{z + 2} \over 5}$$
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