JEE Math Practice Question
If the lines $${{x - 2} \over 1} = {{y - 3} \over 1} = {{z - 4} \over { - k}}$$ and $${{x - 1} \over k} = {{y - 4} \over 2} = {{z - 5} \over 1}$$ are coplanar, then $$k$$ can have :
- A.any value
- B.exactly one value
- C.exactly two values
- D.exactly three values
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