JEE Math Practice Question
If the angle between the line $$x = {{y - 1} \over 2} = {{z - 3} \over \lambda }$$ and the plane $$x+2y+3z=4$$ is $${\cos ^{ - 1}}\left( {\sqrt {{5 \over {14}}} } \right),$$ then $$\lambda $$ equals :
- A.$${3 \over 2}$$
- B.$${2 \over 5}$$
- C.$${5 \over 3}$$
- D.$${2 \over 3}$$
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