JEE Math Practice Question
Let the line $$\,\,\,\,\,$$ $${{x - 2} \over 3} = {{y - 1} \over { - 5}} = {{z + 2} \over 2}$$ lie in the plane $$\,\,\,\,\,$$ $$x + 3y - \alpha z + \beta = 0.$$ Then $$\left( {\alpha ,\beta } \right)$$ equals
- A.$$(-6,7)$$
- B.$$(5,-15)$$
- C.$$(-5,5)$$
- D.$$(6, -17)$$
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