JEE Math Practice Question
If the plane $$2ax-3ay+4az+6=0$$ passes through the midpoint of the line joining the centres of the spheres $${x^2} + {y^2} + {z^2} + 6x - 8y - 2z = 13$$ and $${x^2} + {y^2} + {z^2} - 10x + 4y - 2z = 8$$ then a equals :
- A.$$-1$$
- B.$$1$$
- C.$$-2$$
- D.$$2$$
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