JEE Math Practice Question
If the angel $$\theta $$ between the line $${{x + 1} \over 1} = {{y - 1} \over 2} = {{z - 2} \over 2}$$ and the plane $$2x - y + \sqrt \lambda \,\,z + 4 = 0$$ is such that $$\sin \,\,\theta = {1 \over 3}$$ then value of $$\lambda $$ is :
- A.$${5 \over 3}$$
- B.$${-3 \over 5}$$
- C.$${3 \over 4}$$
- D.$${-4 \over 3}$$
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