JEE Math Practice Question
If the straight lines $$x=1+s,y=-3$$$$ - \lambda s,$$ $$z = 1 + \lambda s$$ and $$x = {t \over 2},y = 1 + t,z = 2 - t,$$ with parameters $$s$$ and $$t$$ respectively, are co-planar, then $$\lambda $$ equals :
- A.$$0$$
- B.$$-1$$
- C.$$ - {1 \over 2}$$
- D.$$-2$$
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