JEE Math Practice Question
The shortest distance from the plane $$12x+4y+3z=327$$ to the sphere $${x^2} + {y^2} + {z^2} + 4x - 2y - 6z = 155$$ is
- A.$$39$$
- B.$$26$$
- C.$$11{4 \over {13}}$$
- D.$$13$$
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