JEE Math Practice Question
In a triangle ABC, if $$\cos \mathrm{A}+2 \cos \mathrm{B}+\cos C=2$$ and the lengths of the sides opposite to the angles A and C are 3 and 7 respectively, then $$\mathrm{\cos A-\cos C}$$ is equal to
- A.$$\frac{3}{7}$$
- B.$$\frac{9}{7}$$
- C.$$\frac{10}{7}$$
- D.$$\frac{5}{7}$$
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