JEE Math Practice Question

If in a triangle ABC, AB = 5 units, $$\angle B = {\cos ^{ - 1}}\left( {{3 \over 5}} \right)$$ and radius of circumcircle of $$\Delta$$ABC is 5 units, then the area (in sq. units) of $$\Delta$$ABC is :

1. A.$$10 + 6\sqrt 2 $$
2. B.$$8 + 2\sqrt 2 $$
3. C.$$6 + 8\sqrt 3 $$
4. D.$$4 + 2\sqrt 3 $$