JEE Math Practice Question
The angles A, B and C of a triangle ABC are in A.P. and a : b = 1 : $$\sqrt 3 $$. If c = 4 cm, then the area (in sq. cm) of this triangle is :
- A.2$$\sqrt 3 $$
- B.4$$\sqrt 3 $$
- C.$${4 \over {\sqrt 3 }}$$
- D.$${2 \over {\sqrt 3 }}$$
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