JEE Math Practice Question
Given $${{b + c} \over {11}} = {{c + a} \over {12}} = {{a + b} \over {13}}$$ for a $$\Delta $$ABC with usual notation. If $${{\cos A} \over \alpha } = {{\cos B} \over \beta } = {{\cos C} \over \gamma },$$ then the ordered triad ($$\alpha $$, $$\beta $$, $$\gamma $$) has a value :
- A.(19, 7, 25)
- B.(7, 19, 25)
- C.(5, 12, 13)
- D.(3, 4, 5)
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