JEE Math Practice Question
In a triangle $$ABC$$, medians $$AD$$ and $$BE$$ are drawn. If $$AD=4$$, $$\angle DAB = {\pi \over 6}$$ and $$\angle ABE = {\pi \over 3}$$, then the area of the $$\angle \Delta ABC$$ is :
- A.$${{64} \over 3}$$
- B.$${8 \over 3}$$
- C.$${{16} \over 3}$$
- D.$${{32} \over {3\sqrt 3 }}$$
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