JEE Math Practice Question

Let T and C respectively be the transverse and conjugate axes of the hyperbola $$16{x^2} - {y^2} + 64x + 4y + 44 = 0$$. Then the area of the region above the parabola $${x^2} = y + 4$$, below the transverse axis T and on the right of the conjugate axis C is :

1. A.$$4\sqrt 6 - {{28} \over 3}$$
2. B.$$4\sqrt 6 - {{44} \over 3}$$
3. C.$$4\sqrt 6 + {{28} \over 3}$$
4. D.$$4\sqrt 6 + {{44} \over 3}$$