JEE Math Practice Question
Let the foci of the ellipse $$\frac{x^{2}}{16}+\frac{y^{2}}{7}=1$$ and the hyperbola $$\frac{x^{2}}{144}-\frac{y^{2}}{\alpha}=\frac{1}{25}$$ coincide. Then the length of the latus rectum of the hyperbola is :
- A.$$\frac{32}{9}$$
- B.$$\frac{18}{5}$$
- C.$$\frac{27}{4}$$
- D.$$\frac{27}{10}$$
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