JEE Math Practice Question
A normal to the hyperbola, 4x2 $$-$$ 9y2 = 36 meets the co-ordinate axes $$x$$ and y at A and B, respectively. If the parallelogram OABP (O being the origin) is formed, then the ocus of P is :
- A.4x2 + 9y2 = 121
- B.9x2 + 4y2 = 169
- C.4x2 $$-$$ 9y2 = 121
- D.9x2 $$-$$ 4y2 = 169
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