JEE Math Practice Question
If 2 and 6 are the roots of the equation $$a x^2+b x+1=0$$, then the quadratic equation, whose roots are $$\frac{1}{2 a+b}$$ and $$\frac{1}{6 a+b}$$, is :
- A.$$x^2+8 x+12=0$$
- B.$$2 x^2+11 x+12=0$$
- C.$$4 x^2+14 x+12=0$$
- D.$$x^2+10 x+16=0$$
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