JEE Math Practice Question
Let $$\alpha, \beta, \gamma$$ be the three roots of the equation $$x^{3}+b x+c=0$$. If $$\beta \gamma=1=-\alpha$$, then $$b^{3}+2 c^{3}-3 \alpha^{3}-6 \beta^{3}-8 \gamma^{3}$$ is equal to :
- A.21
- B.19
- C.$$\frac{169}{8}$$
- D.$$\frac{155}{8}$$
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