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JEE Math Practice Question

Let $$\alpha, \beta$$ be the roots of the equation $$x^{2}-\sqrt{2} x+2=0$$. Then $$\alpha^{14}+\beta^{14}$$ is equal to

  1. A.$$-64$$
  2. B.$$-64 \sqrt{2}$$
  3. C.$$-128 \sqrt{2}$$
  4. D.$$-128$$

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