JEE Math Practice Question
$$ \text { Let } S=\left\{x \in[-6,3]-\{-2,2\}: \frac{|x+3|-1}{|x|-2} \geq 0\right\} \text { and } $$ $$T=\left\{x \in \mathbb{Z}: x^{2}-7|x|+9 \leq 0\right\} \text {. } $$ Then the number of elements in $$\mathrm{S} \cap \mathrm{T}$$ is :
- A.7
- B.5
- C.4
- D.3
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