JEE Math Practice Question
The sum of all the real roots of the equation $$({e^{2x}} - 4)(6{e^{2x}} - 5{e^x} + 1) = 0$$ is
- A.$${\log _e}3$$
- B.$$ - {\log _e}3$$
- C.$${\log _e}6$$
- D.$$ - {\log _e}6$$
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