JEE Math Practice Question
Let a, b $$ \in $$ R, a $$ \ne $$ 0 be such that the equation, ax2 – 2bx + 5 = 0 has a repeated root $$\alpha $$, which is also a root of the equation, x2 – 2bx – 10 = 0. If $$\beta $$ is the other root of this equation, then $$\alpha $$2 + $$\beta $$2 is equal to :
- A.28
- B.24
- C.26
- D.25
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