JEE Math Practice Question

Let $$\lambda \ne 0$$ be in R. If $$\alpha $$ and $$\beta $$ are the roots of the equation, x2 - x + 2$$\lambda $$ = 0 and $$\alpha $$ and $$\gamma $$ are the roots of the equation, $$3{x^2} - 10x + 27\lambda = 0$$, then $${{\beta \gamma } \over \lambda }$$ is equal to:

1. A.36
2. B.9
3. C.27
4. D.18