JEE Math Practice Question

If $$\alpha $$ and $$\beta $$ are the roots of the equation x2 + px + 2 = 0 and $${1 \over \alpha }$$ and $${1 \over \beta }$$ are the roots of the equation 2x2 + 2qx + 1 = 0, then $$\left( {\alpha - {1 \over \alpha }} \right)\left( {\beta - {1 \over \beta }} \right)\left( {\alpha + {1 \over \beta }} \right)\left( {\beta + {1 \over \alpha }} \right)$$ is equal to :

1. A.$${9 \over 4}\left( {9 - {q^2}} \right)$$
2. B.$${9 \over 4}\left( {9 + {q^2}} \right)$$
3. C.$${9 \over 4}\left( {9 - {p^2}} \right)$$
4. D.$${9 \over 4}\left( {9 + {p^2}} \right)$$