JEE Math Practice Question
If $$\lambda $$ be the ratio of the roots of the quadratic equation in x, 3m2x2 + m(m – 4)x + 2 = 0, then the least value of m for which $$\lambda + {1 \over \lambda } = 1,$$ is
- A.$$ - 2 + \sqrt 2 $$
- B.4$$-$$3$$\sqrt 2 $$
- C.2 $$-$$ $$\sqrt 3 $$
- D.4 $$-$$ 2$$\sqrt 3 $$
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